Respuesta :

Answer:

let [tex]x[/tex] = height of rectangle

Given:

  • height of rectangle = diameter of circle
  • length of rectangle = 3 × height of rectangle

Therefore,

  • height of rectangle = [tex]x[/tex]
  • diameter of circle = [tex]x[/tex]
  • radius of circle = [tex]\dfrac{1}{2}x[/tex]
  • length of rectangle = [tex]3x[/tex]

Shaded area = area of rectangle - area of circle

Area of rectangle = length × height

                             = [tex]3x \times x[/tex]

                             = [tex]3x^2[/tex]

Area of circle = [tex]\pi r^2[/tex]

                       [tex]=\pi \left(\dfrac{1}{2}x\right)^2[/tex]

                       [tex]=\dfrac14\pi x^2[/tex]

[tex]\implies \textsf{shaded area}=3x^2-\dfrac14\pi x^2[/tex]

If the radius = 2 cm, then the diameter ([tex]x[/tex]) = 4 cm

Substituting [tex]x = 4[/tex] into the equation:

[tex]\implies \textsf{shaded area}=3(4)^2-\dfrac14\pi (4)^2[/tex]

[tex]\implies \textsf{shaded area}=48-4\pi[/tex]

[tex]\implies \textsf{shaded area}=4(12-\pi) \textsf{ cm}^2[/tex]

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