At constant conditions, 1000 mL of the chlorine gas will be required to yield 1.00 L of dichlorine trioxide.
Stoichiometric equation
From the equation of the reaction:
2Cl2(g)+3O2(g)→2Cl2O3(g)
Mole ratio of Cl2O3 and Cl2 = 1:1
At standard conditions, 1 mole of gas equals 22.4 L volume.
1.00 L of Cl2O3 would, therefore, be:
1 x 1/24 = 0.04 moles
Equivalent mole of Cl2 = 0.04 moles.
Thus, 1.00 L or 1000 mL of Cl2 will also be required.
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