The possible outcomes of the fair coin and the dice is the sample space
The items are given as:
Coin = 1
Dice = 1
The sample space of both items are:
Coin = {H,T}
Dice = {1,2,3,4,5,6}
So, the list of possible outcomes is: {H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}
From the above list, there is only one outcome that has a head and a 3 out of 12 possible outcomes
So, the probability of getting a head and a 3 is:
p = 1/12
Hence, the probability of getting a head and a 3 is 1/12
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