Question

Solve for x :-
$\:$
${ \large{ \rm{ \frac{7x + 14}{3} - \frac{17 - 3x}{5} = 6x - \frac{4x + 2}{3} - 5 }}}$
$\rule{200pt}{5pt}$
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Answer 1

We need to find value of x from the equation, so let write the equation first;

${:\implies \quad \sf \dfrac{7x+14}{3}-\dfrac{17-3x}{5}=6x-\dfrac{4x+2}{3}-5}$

Taking LCM both sides ;

${:\implies \quad \sf \dfrac{35x+70-(51-9x)}{15}=\dfrac{18x-(4x+2)-15}{3}}$

Multiplying both sides by 15 and simplifying ;

${:\implies \quad \sf 35x+70-51+9x=5(18x-4x-2-15)}$

${:\implies \quad \sf 44x+19=5(14x-17)}$

${:\implies \quad \sf 44x+19=70x-85}$

${:\implies \quad \sf 70x-44x=19+85}$

${:\implies \quad \sf 26x=104}$

${:\implies \quad \sf x=\dfrac{104}{26}=\boxed{\bf 4}}$

Hence, The required answer is 4

Answer 2

Given: {(7x + 14)/3} - {(17 - 3x)/5} = 6x - {(4x + 2)/3} - 5

Asked: Find the value of x = ?

Explanation: Given equation is {(7x + 14)/3} - {(17 - 3x)/5} = 6x - {(4x + 2)/3} - 5

⇛{(7x + 14)/3} - {(17 - 3x)/5} = {(6x)/1} - {(4x + 2)/3} - (5/1)

⇛{(7x*5 + 14*5 - 17*3 + 3x*3)/15} = {(6x*3 - 4x*1 - 2*1 - 5*3)/3}

⇛{(35x + 70 - 51 + 9x)/15} = {(18x - 4x - 2 - 15)/3}

⇛{(35x + 9x + 70 - 51)/15} = {(18x - 4x - 2 - 15)/3}

⇛{(44x + 19)/15} = {(14x - 17)/3}

⇛[{1/15}(44x + 19)] = [{1/3}(14x - 17)}]

⇛{(44x + 19)/15} = {(14x - 17)/3}

Since (a/b) = (c/d) ⇛a(d) = b(c) ⇛ad = bc

Where, a = 44x + 19, b = 15

c = 14x - 17 and d = 3

On applying cross multiplication then

⇛3(44x + 19) = 15(14x - 17)

Multiply the numbers outside of the bracket with numbers in the bracket.

⇛132x + 57 = 210x - 255

Shift the variable value on LHS and constant value on RHS.

⇛132x - 210x = -255 - 57

Subtract the values on LHS and RHS.

⇛(-78x) = (-312)

Shift the number (-78) from LHS to RHS.

⇛x = {(-312)/(-78)

Simplify the RHS fraction to get the final value of x.

⇛x = 4/1

Therefore, x = 4

Answer: Hence, the value of x for the given problem is 4.

EXPLORE MORE:

Verification:

Check whether the value of x for the given problem is true or false.

If x = 4 then LHS of the equation is

{(7x + 14)/3} - {(17 - 3x)/5}

= [{7(4) + 14}/3] - [{17 - 3(4)}/5]

= {(7*4 + 14)/3} - {(17 - 3*4)/5}

= {(28 + 14))3} - {(17 - 12)/5}

= (42/3) - (5/5)

= (42/3) - 1

= (42/3) - (1/1)

= {(42 - 1*3)/3

= {(42 - 3)/3}

= (39/3)

= 13/1

= 13

And RHS = 6x - {(4x + 2)/3} - 5

= 6(4) - [{4(4) + 2}/3] - 5

= 24 - {(16 + 2)/3} - 5

= 24 - (18/3) - 5

= 24 - (6/1) - 5

= (24/1) - (6/1) - (5/1)

= (24*1 - 6*1 - 5*1)/1

= (24 - 6 - 5)/1

= (24 -11)/1

= 13/1

= 13

On comparing with both the sides, we notice that LHS = RHS is true for x = 4

Hence, verified.

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