10x^2 - 13x = 3 a = 10, b = -13, c = -3 (quadratic formula? icba to write it sos!!)
-3 both sides
10x^2 - 13x - 3 = 0 -3 x 10 = -30 (products of -30 and equal to -13 are 15, -2 (so we use this))
10x^2 - 2x + 15x - 3 = 0
factorising now
2x (5x - 1) + 3 (5x - 1)
the brackets have to be the same
(2x + 3) (5x - 1)
2x - 3 = 0 ——— 5x + 1 = 0 (switch the signs forgot y tbf)
add 3 to both sides ——— minus 1 on sides
2x = 3 ——— 5x = -1
divide by 2 both sides ——— divide both by 5
x = 3/2 ——— x = -1/5
naw cus I spent so long on this for the answer to be wrong dam-n
