Find the volume of the sphere. Round your answer to the nearest tenth.
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We know,
[tex]{\qquad { \longrightarrow \pmb {\sf Volume_{(Sphere)} = \dfrac{4}{3} \pi {r}^{3} }}}[/tex]
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Here,
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Substituting the values in the formula :
[tex]{ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{3} \times \dfrac{22}{7} \times {\bigg(14 \bigg)}^{3} }}}[/tex]
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[tex]{ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{3} \times \dfrac{22}{7} \times {2744 }}}}[/tex]
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[tex]{ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{3} \times \dfrac{22}{ \cancel7} \times \cancel{2744 }}}}[/tex]
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[tex]{ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{ \cancel3} \times {22} \times \cancel{392 }}}}[/tex]
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[tex]{ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = {4} \times {22} \times {130.66 }}}}[/tex]
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[tex]{ \longrightarrow {\qquad {\pmb{\mathfrak{ Volume_{(Sphere)} = { 11498.66 }}}}}}[/tex]
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Therefore,