Question

A gas at a constant pressure occupies 2.24 L at 52 C. If the sample is cooled until it
takes up 1.66 Lwhat is the new temperature?

Answer 1

The new temperature of the gas is -32.15 °C or 240.85 K.

The new temperature of the gas can be calculated using the mathematical representation of Charles's law

Charles's law

Charles's law states that at constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature.

Formula:

• V/T = V'/T'................ Equation 1

Where:

• V = Initial volume of the gas
• T = Initial temperature of the gas
• V' = Final Volume of the gas
• T' = Final temperature of the gas.

Make T' The subject of the equation

• T' = V'T/V............. Equation  2

From the question,

Given:

• V = 2.24 L
• V' = 1.66 L
• T = 52 °C

We need to convert the initial temperature T above from °C to Kelvin (K) by adding 273.

• T = (273+52) = 325 K

Substitute these values into equation 2

• T' = (1.66×325)/2.24
• T' = 539.5/2.24
• T' = 240.85 K.
• T' = -32.15 °C.

Hence, The new temperature of the gas is -32.15 °C.

Learn more about Charles's law here: https://brainly.com/question/25290815