Using the combination formula, it is found that there are 129 different combinations.
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this problem, combinations of 1, 2 or 3 pieces from a set of 9 are taken, hence:
[tex]C_{9,1} = \frac{9!}{1!8!} = 9[/tex]
[tex]C_{9,2} = \frac{9!}{2!7!} = 36[/tex]
[tex]C_{9,3} = \frac{9!}{3!6!} = 84[/tex]
Then, the total is of:
T = 9 + 36 + 84 = 129.
More can be learned about the combination formula at https://brainly.com/question/25821700