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Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients. Br2(l) + I2 (s) --> IBr3(g)

Respuesta :

Answer:

3 Br₂(l) +  I₂ (s) --> 2 IBr₃ (g)

Explanation:

After multiplying the coefficients and the subscripts, this would leave you with:

Reactants: 6 Br and 2 I

Products: 6 Br and 2 I

These are the lowest possible coefficients because you cannot further divide the coefficients and still get a whole number.

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