Question

A container with a volume 2.0L is filled with a gas at a pressure of 1.5 atm. By decreasing the volume of the container to 1.0 L, what is the resulting pressure? Type in your answer using the correct number of significant figures . Remember to use formula for Boyles law; P1V1=P2V2

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Answer 1

Answer:

P2 = 3

Explanation:

u know that:

V1 = 2.0L

P1 = 1.5 atm

V2 = 1.0L

P2 = ?        (p1v1=p2v2)

1.5x2 = P2x1.0

3=P2x1.0    =>> 3.0 =P2

divided both side by 1.0 the remove 1.0 (left P2)

Answer 2

The pressure by decreasing the volume to 1 L will be  $P_2=3 \ atm$  

what will be a new pressure?

The given data is that

Volume    $V_1=2 \ Litres$

Pressure  $P_1=1.5\ atm$

When volume is reduced to

$V_2=1\ liters$

By using Boyles Law

$P_1V_1=P_2V_2$

$P_2=\dfrac{P_1V_1}{V_2}$

$P_2=\dfrac{2\times 1.5}{1} =3 \ atm$

Thus the pressure by decreasing the volume to 1 L will be  $P_2=3 \ atm$  

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