Question

A researcher plans to use a random sample of houses to estimate the mean size (in square feet) of the houses in a large population. The researcher is deciding between a 95% confidence level and a 99% confidence level. Compared with a 95% confidence interval, a 99% confidence interval will be

Answer 1

Considering the margin of error, it is found that the 99% confidence interval will be wider than the 95% confidence interval.

What is the margin of error of a confidence interval?

It is given by:

$M = z\frac{s}{\sqrt{n}}$

In which:

• z is the critical value, which increases with a higher confidence level.

• s is the standard deviation.

• n is the sample size.

From this, we get that the margin of error is direct proportional to the critical value, hence $z_{99}>z_{95}$, which means that the 99% confidence interval will be wider, that is, it will have a larger margin of error, than the 95% confidence interval.

More can be learned about confidence intervals at https://brainly.com/question/25890103