Question

NO LINKS!!! Please help me with this problem. Part 3
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Answer 1

Answer:

Using diagram from your another question .

• AB=4
• BC=10

Use Pythagorean theorem

$\\ \rm\longmapsto AC^2=4^2+10^2=16+100=116$

$\\ \rm\longmapsto AC=10.77$

• cos20=0.94

• BC/AC=10/10.77=0.91

Not satisfied (Close but we can't ignore 0.03)

Let required BC be x

$\\ \rm\longmapsto \dfrac{x}{10.77}=cos20$

$\\ \rm\longmapsto x=0.94(10.77)=10.124ft$

Camera should be shifted 0.124ft left