I will mark brainlyist
What are the values of the variables in the triangle below?

Answer:
x = 3sqr3, y = 9
Step-by-step explanation:
Use SOH CAH TOA, to solve this.
Here I know the hypotenuse, so I could use either SOH either CAH or both to find the 2 unknowns.
To find y, I would use SOH, which is Sin(angle) = opposite/hypotenuse.
When I rearrange it, I get Sin(angle)*hypotenuse = opposite. Now let's fill in with the values to give:
Sin(30)*6sqr3 = 3sqr3
And then to find x, let's use CAH, which is Cos(angle) = adjacent/hypotenuse.
Rearrange it to get Cos(angle)*hypotenuse = adjacent. This gives us a side x with a value of:
Cos(30)*6sqr3 = 9