Question

A slot machine has 3 dials. Each dial has 40 positions, two of which are "Jackpot." To win the jackpot, all three dials must be in the "Jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot?

Answer 1

Answer: there is a 1.2% of winning

Step-by-step explanation: there is a 1.2% chance of winning.

Answer 2

Step-by-step explanation:

The odds of one player that wins the jackpot should be 0.00156%.

Given that,

There are 3 dials.

In each dial, there are 40 positions.

So, the probability of receiving the jackpot should be \frac{1}{40}

40

1

Now the odds of one player that wins the jackpot should be

\begin{gathered}= \frac{1}{40} \times \frac{1}{40} \times \frac{1}{40} \\\\\end{gathered}

=

40

1

×

40

1

×

40

1

= 0.00156%

Therefore we can conclude that the odds of one player that wins the jackpot should be 0.00156%.