Question

Math Practice #2 – Electricity
Ms. Lolich/Physical Science
READ: Show formulas and all steps for each problem for full credit. Round your answers to the nearest hundredth. Put the final answer in the box for each problem. Don’t forget to label units!
1. A small electrical pump is labeled with a rating of 3 amps and a resistance of 40 ohms. What voltage was it meant to run at?
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2. A nine volt battery is hooked up to a light bulb with a rating of three ohms. How much current passes through the light?
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3. A lamp is plugged into the wall outlet, which is providing 110 volts. An ammeter attached to the lamp shows 2 amps flowing through the circuit. How many ohms of resistance is the lamp providing?
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4. How much current flows through a 20 Ohm resistance when 6 Volts is applied? V=
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5. How many volts are required to send 0.5 ampere through a 60 Ohm circuit? V=
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6.How much resistance is a lamp if 0.20 amperes flows when a 6.0 Volt battery is applied? V=
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7. If the potential difference is 120 volts and the resistance is 40 ohms, what is the current? V=
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8. What voltage produces a current of 400 amps with a resistance of 50 ohms? V=
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9. What is the resistance of a light bulb if a 120-volt potential difference produces a current of 0.9
amperes?
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10. A 12-volt battery produces a current of 27 amperes. What is the resistance? V=
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Answer 1

(1) The voltage in the circuit is 120 V.

(2) The current in the circuit is 3 A.

(3) The resistance provided by the lamp in the circuit is 55 ohms.

(4) The current in the circuit is 0.3 A.

(5) The voltage in the circuit is 30 V.

(6) The resistance provided by the lamp in the circuit is 30 ohms.

(7) The current in the circuit is 3 A.

(8) The voltage in the circuit is 20,000 V.

(9) The resistance provided by the light bulb in the circuit is 133.33 ohms.

(10) The resistance provided in the circuit is 0.44 ohm.

1.0 Voltage in the circuit

The voltage in the circuit is determined by applying Ohm's law as shown below;

V = IR

V = 3 x 40

V = 120 V

2.0 Current in the circuit

The current in the circuit is determined by applying Ohm's law as shown below;

I = V/R

I = 9/3

I = 3 A

3.0 Resistance of the circuit

The resistance provided by the lamp in the circuit is determined by applying Ohm's law;

R = V/I

R = 110/2

R = 55 ohms

4.0 Current in the circuit

The current in the circuit is determined by applying Ohm's law as shown below;

I = V/R

I = 6/20

I = 0.3 A

5.0 Voltage in the circuit

The voltage in the circuit is determined by applying Ohm's law as shown below;

V = IR

V = 0.5 x 60

V = 30 V

6.0 Resistance of the circuit

The resistance provided by the lamp in the circuit is determined by applying Ohm's law;

R = V/I

R = 6/0.2

R = 30 ohms

7.0 Current in the circuit

The current in the circuit is determined by applying Ohm's law as shown below;

I = V/R

I = 120/40

I = 3 A

8.0 Voltage in the circuit

The voltage in the circuit is determined by applying Ohm's law as shown below;

V = IR

V = 400 x 50

V = 20,000 V

9.0 Resistance of the light bulb

The resistance provided by the light bulb in the circuit is determined by applying Ohm's law;

R = V/I

R = 120/0.9

R = 133.33 ohms

10.0 Resistance of the circuit

The resistance provided in the circuit is determined by applying Ohm's law;

R = V/I

R = 12/27

R = 0.44 ohm

Learn more about Ohms law here: https://brainly.com/question/231741