Respuesta :

For a rhombus, two diagonals perpendicularly intersect to each other.
Therefore, angle of FHG=90 degree
-2x+8=90
-2x=82
x=-41
Pls mark me as the Brainliest as I really need it, thanks!

Answer:

x = -41

Step-by-step explanation:

Diagonals of a rhombus are perpendicular bisectors of each other.

Therefore, m∠FHG = m∠GHD = m∠DHE = m∠EHF = 90°

If m∠FHG = (-2x + 8)° and m∠FHG = 90° then

⇒ -2x + 8 = 90

subtract 8 from both sides:

⇒ -2x + 8 - 8 = 90 - 8

⇒ -2x = 82

divide both sides by -2:

⇒ -2x ÷ -2 = 82 ÷ -2

⇒ x = -41

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