Solve for x of this equation
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Diagonals of a rhombus are perpendicular bisectors to each other
[tex]\\ \rm\rightarrowtail NR=RP[/tex]
[tex]\\ \rm\rightarrowtail 2x+1=91[/tex]
[tex]\\ \rm\rightarrowtail 2x=90[/tex]
[tex]\\ \rm\rightarrowtail x=45[/tex]
Answer:
x = 45
Step-by-step explanation:
Properties of a rhombus:
As the diagonals bisect each other (bisect means to divide into two equal parts) then NR = RP
So, 91 = 2x + 1
Subtract 1 from both sides:
⇒ 90 = 2x
Divide both sides by 2
⇒ x = 45