Question -:
The area of the rectangle whose length is [tex]\frac{7}{4}[/tex] cm and breadth [tex]\frac{8}{4}[/tex] cm is ---------- cm²
Explanation -:
Given -:
- Length = [tex]\frac{7}{4}[/tex] cm
- Breadth = [tex]\frac{8}{4}[/tex] cm
To Find -:
Solution -:
We know,
[tex] ☢ \: \large\boxed{ \rm{ Area_{(rectangle)} = L × B }}[/tex]
Where,
- L stand for Length
- B stand for Breadth
Substituting the values of length = [tex]\frac{7}{4}[/tex] cm and breadth = [tex]\frac{8}{4}[/tex] cm in the given formula
[tex] \large\sf{ Area_{(rectangle)} = \dfrac{7}{4} × \dfrac{8}{4}}[/tex]
[tex] \rightarrow \large\sf Area_{(rectangle)} = \dfrac{7 \times 8}{4 \times 4} [/tex]
[tex] \large\sf{ Area_{(rectangle)} = \dfrac{7 \times \cancel{ 8} \: ^{ \cancel{2}} }{ \cancel{4} \: ^{2} \times \cancel{4} } = \dfrac{7}{2} {cm}^{2} }[/tex]
Area of the rectangle = [tex]\frac{7}{2}[/tex] cm².
[tex] \underline {\rule{60mm}{2pt}}[/tex]
