my math homework in khan due at 11 pm
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Given :-
[tex] \\ \\ [/tex]
To find :-
[tex] \\ \\ [/tex]
Solution :-
we know:
[tex] \\ [/tex]
[tex] \bigstar \boxed{ \rm Volume \: of \: sphere = \frac{4}{3}\pi {r}^{3} }[/tex]
[tex] \\ [/tex]
So:-
[tex] \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4}{3}\pi {r}^{3} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4}{3}\pi \times {7}^{3} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4}{3}\pi \times {7} \times 7 \times 7 \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4}{3}\pi \times 343 \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4}{3} \times 3.14\times 343 \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4}{3} \times 1077.02 \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4 \times1077.02 }{3} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \sf Volume \: of \: sphere = \frac{4308.08}{3} \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \pmb{\sf Volume \: of \: sphere =1436.03(approx)} \\ [/tex]
[tex] \\ \\ [/tex]
❥ W᭄indy✞Mint࿐
We are given with a sphere whose radius is 7 units and we need to find the volume of the sphere , but before starting let's recall that ;
Where r is the radius of the sphere . So , now in this question applying the same concept we have ;
[tex]{:\implies \quad \sf Volume_{(Sphere)}=\dfrac{4}{3}\pi (7)^{3}}[/tex]
[tex]{:\implies \quad \sf Volume_{(Sphere)}=\dfrac{4}{3}\pi \times 343}[/tex]
[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{Volume_{(Sphere)}=\dfrac{1372\pi}{3}\:\: units^{3}}}}[/tex]