Question

A cart of mass m1 = 0.500 kg moves with a velocity of 0.900 m/s to the right on a frictionless track. It collides with another cart of mass m2 = 0.500 kg at rest. Car m1 stops and m2 moves in the direction that m1 was traveling. What is the magnitude of the final velocity of m2? Enter you answer in m/s.

Answer 1

The final velocity of the cart m2 is 0.9 m/s.

What is velocity?

Velocity can be defined as the rate of change of displacement. The S.I unit of velocity is m/s

To calculate the magnitude of the final velocity of car m2, we apply the formula below.

Formula:

• mu+m'u' = mv+m'u'............. Equation 1

Where:

• m = mass of the cart m1
• m' = mass of cart m2
• u = initial velocity of cart m1
• initial velocity of cart m2
• v = final velocity of cart m1
• v' = final velocity of cart m2

From the question,

Given:

• m = 0.5 kg
• m' = 0.5 kg
• u = 0.9 m/s
• u' = 0 m/s
• v = 0 m/s

Substitute these values into equation 1

• 0.5(0.9)+0.5(0) = 0.5(0)+0.5v'
• 0.45 = 0.5v'
• v' = 0.45/0.5
• v' = 0.9 m/s.

Hence, The final velocity of the cart m2 is 0.9 m/s.

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