Question

(PLS HELP)The diameter of a cylindrical water tank is 12 ft, and its height is 17 ft. What is the volume of the tank?
Use the value 3.14 for л, and round your answer to the nearest whole number. Be sure to include the correct unit in your answer.

Answer 1

Solution:

We know that:

• Volume of a cylinder = πr²h.

Finding the radius of the cylindrical water tank:

$\rightarrow Diameter = 2(Radius)$

$\rightarrow Radius = \frac{Diameter}{2} = \frac{12}{2} = 6 \ feet$

Now, let's find the volume of the cylinder by substituting the radius.

Finding the volume of the cylinder:

$\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = \pi r^{2} h$

$\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = (3.14)( 6^{2})( 17)$

$\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = (3.14)( 36)( 17)$

$\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = 1921.68 \ feet^{3}$

Rounding to the nearest whole number:

$\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = 1921.68 \ feet^{3}$

$\rightarrow \tex V \tex o \tex l \tex u \tex m \tex e\tex \ \tex of \tex \ c \tex y \tex l \tex i \tex n \tex d \tex e \tex r = 1922 \ feet^{3} \ (Rounded \ to \ nearest \ whole \ number)$  

Thus, the volume of the cylinder is 1922 feet³ (Rounded).

Answer 2

• Radius=r=12/2=6ft
• Height=h=17ft

$\\ \rm\rightarrowtail V=\pi r^2h$

$\\ \rm\rightarrowtail V=\pi (6)^2(17)$

$\\ \rm\rightarrowtail V=36(17)\pi$

$\\ \rm\rightarrowtail V=612\pi$

$\\ \rm\rightarrowtail V=1921.68ft^3$