Question

John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is. The probability that he throws the dart into the 10-point ring is. What is the probability that he either hits a Bull’s eye or scores 10 points?.

Answer 1

The probability that the John either hits a Bull’s eye or scores 10 points in the game of darts is 2/5.

What is probability?

Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event. The probability of an event can not be more than the number 1.

John is playing a game of darts. In this game of dart,

• The probability that he throws a dart into the center of the dart board (the Bull’s eye) is 1/10.
• The probability that he throws the dart into the 10-point ring is 3/10.

The probability that he either hits a Bull’s eye or scores 10 points is equal to the sum of the probability he hits the bull's eye and the probability that he throws the dart into the 10-points ring.

Let, the probability that he either hits a Bull’s eye or scores 10 points is P. Thus,

$P=\dfrac{1}{10}+\dfrac{3}{10}\\P=\dfrac{4}{10}\\P=\dfrac{2}{5}$

Hence, the probability that the John either hits a Bull’s eye or scores 10 points in the game of darts is 2/5.

Learn more about the probability here;

https://brainly.com/question/24756209

Answer 2

Answer:

Option D is the correct answer

Step-by-step explanation:

D.$\frac{2}{5}$