Question

twice the square of an integer added to 6 is 12 times larger than the integer, form qn equation​

Answer 1

Integer be x

$\\ \rm\rightarrowtail 2x^2+6=12x$

$\\ \rm\rightarrowtail 2x^2-12x+6=0$

Equation is

$\\ \rm\rightarrowtail x^2-6x+3=0$