Given :
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To Find :
⠀
Solution :
We know that,
[tex]\qquad \pmb{\bf{Area_{(Rectangle)}= Length \times width }}[/tex]
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So, Substituting the given values :
[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = 2 \dfrac{4}{5} \times 2 \dfrac{3}{7} }}[/tex]
[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{14}{5} \times \dfrac{17}{7} }}[/tex]
[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{ \cancel{14}}{5} \times \dfrac{17}{ \cancel{7}} }}[/tex]
[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{2}{5} \times {17} }}[/tex]
[tex] \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{34}{5} }}[/tex]
[tex] \: \qquad \dashrightarrow \sf{{Area _{(Rectangle)} = 6 \dfrac{4}{5} \: {mm}^{2} }}[/tex]
Therefore,