The area of Jill's soccer net is 3 times larger than area of Peter's soccer net.
The area of Peter's soccer net is determined by using area of rectangle as shown below;
A1 = 5.5 ft x 4 ft
A1 = 22 ft²
A2 = 5.5 ft x 12 ft
A2 = 66 ft²
A2/A1 = 66/22
A2/A1 = 3
Thus, the area of Jill's soccer net is 3 times larger than area of Peter's soccer net.
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