Question

Find the value of the test statistic z using z = .

A claim is made that the proportion of children who play sports is less than 0.5, and the sample statistics include n = 1671 subjects with 30% saying that they play a sport.

A. 33.38
B. –33.38
C. 16.35
D. –16.35

Answer 1

Answer:

$\sf z = -16.35$

formula:

$\sf z = \dfrac{s-p}{\sqrt{\dfrac{p(1-p)}{n} } }$

Here s = 0.3, p = 0.5, n = 1671

solve:

$\rightarrow \sf z = \dfrac{0.30-0.5}{\sqrt{\dfrac{0.5(1-0.5)}{1671} } }$

$\rightarrow \sf z = \dfrac{-0.2}{\sqrt{\dfrac{0.25}{1671} } }$

$\rightarrow \sf z = -16.35$