Question

What is the solution to log[sub=2]9x-log[sub=2]^3=3
x = three-eighths
x = eight-thirds
x = 3
x = 9

Answer 1

Step-by-step explanation:

$\begin{aligned}\log_2(9x)-\log_2(3)&=3\\\log_2\left(\frac{9x}{3}\right)&=3\\\log_2(3x)&=\log_2(2^3)\\3x&=2^3\\3x&=8\\x&=\frac{8}{3}\end{aligned}$