Question

Sucrose (C₁₂H₂₂O₁₁) is combusted in air according to the following reaction:
C₁₂H₂₂O₁₁(s) + O₂(g) → CO₂(g) + H₂O(l)
How many grams of carbon dioxide would be produced by the complete combustion of 2.05 moles of sucrose in the presence of excess oxygen?

Answer 1

The mass of carbon dioxide that would be produced by the complete combustion of 2.05 moles of sucrose is 1,082.4 g.

Complete combustion of the sucrose

The complete combustion of sucrose in excess oxygen is given as follows;

C₁₂H₂₂O₁₁(s) + O₂(g) → CO₂(g) + H₂O(l)

balanced chemical equation is below;

C₁₂H₂₂O₁₁(s) + 12O₂(g) → 12CO₂(g) + 11H₂O(l)

from the reaction above;

1 mole of sucrose ----------> 12 mole of carbon dioxide

2.05 mole of sucrose ------> ?

= 2.05 x 12

= 24.6 moles

Mass of carbon dioxide

1 mole of carbon dioxide = 44 g/mole

24.6 moles = ?

= 24.6 x 44

= 1,082.4 g

Thus, the mass of carbon dioxide that would be produced by the complete combustion of 2.05 moles of sucrose is 1,082.4 g.

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