Question

what is the invers function of f(x)=(n+1)^3?

Answer 1

Answer:

$f^{-1}(x)=\sqrt[3]{x}-1$

Step-by-step explanation:

$f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1$

Graphing both inverses, they will be symmetrical about the line $y=x$.