Question

1) A baseball is thrown in the air with an initial velocity of 18 meters/second from a height of 1.5 meters: Which equation represents the ball's height, h, in meters, as a function of time, t, in seconds?

Answer 1

• Initial velocity=18m/s^2
• h=1.5m
• g=10m/s^2

Now apply second equation of kinematics

$\\ \rm\hookrightarrow h=ut-\dfrac{1}{2}gt^2$

$\\ \rm\hookrightarrow h=18t-1/2(10)t^2$

$\\ \rm\hookrightarrow h=18t-5t^2$