Answer:
A. The edge lengths of the smaller figure are less than half those of the large figure.
[tex]\sf Scale\:factor=\dfrac13[/tex]
Step-by-step explanation:
From inspection of the graph, the pre-image is QRST and the dilated image is Q'R'S'T'.
We can see that Q'R'S'T' is a reduction of QRST since it is smaller.
Inspect the length of the corresponding line segments of both images and compare.
T'S' = 3 units
TS = 9 units
[tex]\sf \dfrac{T'S'}{TS}=\dfrac{3}{9}=\dfrac13[/tex]
Therefore, T'S' is [tex]\sf \frac13[/tex] the length of TS.
As [tex]\sf \frac13 < \frac12[/tex], the edge lengths of the smaller figure are less than half those of the large figure (answer option A)
The scale factor is the amount we have to multiply the sides of QRST by to get Q'R'S'T'. Therefore, the scale factor for the side lengths in this dilation is [tex]\sf \frac13[/tex]
