»f(x) = 7x² - 3x + 7
»f(2) = 7(2)² - 3(2) + 7
»f(2) = 7(4) - 6 + 7
»f(2) = 28 - 6 + 7
»f(2) = 29
»f(-1) = 7(-1)² - 3(-1) + 7
»f(-1) = 7(1) + 3 + 7
»f(-1) = 7 + 3 + 7
»f(-1) = 17
»f(0) = 7(0)² - 3(0) + 7
»f(0) = 7(0) - 0 + 7
»f(0) = 0 - 0 + 7
»f(0) = 7
so, f(2) + f(-1) + f(0) is