Answer:
[tex]9.8ms^{-2}[/tex]
Explanation:
using the equation :
[tex]acceleration = \frac{final velocity - initial velocity}{timetaken} \\ a =\frac{v-u}{t}[/tex]
where v is 98m/s
u is 0m/s
t is 10seconds
[tex]a=\frac{98m/s- 0m/s}{10} \\a=\frac{98}{10}\\ a=9.8m/s^{2}[/tex]