Question

A 750 kg roller coaster car drops from rest at a height of 90 m along a frictionless track. What is velocity of the roller coaster at the top of a second hill that is 60 m high? Show work

Answer 1

The velocity of the roller coaster at the top of the second hill is 24.25 m/s.

What is velocity?

Velocity is the rate of change of displacement. The s.i unit is m/s

To calculate the velocity of the coaster car, we use the formula below.

Formula:

• mg(H-h) = mv²/2............... Equation 1

Where:

• m = mass of the coaster car
• H = Height of drop
• h = Height of the second hill
• v = velocity of the roller coaster.

From the question,

Given:

• m = 750 kg

• H = 90 m

• h = 60 m
• g = constant = 9.8 m/s²

Substitute these values into equation 1

• 750(9.8)(90-60) = 750(v²)/2

Solve for v

• 375v² = 220500
• v² = 220500/375
• v² = 588
• v = √588
• v = 24.25 m/s

Hence, The velocity of the roller coaster at the top of the second hill is 24.25 m/s.

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