Question

Question 2 of 10
Which of the following are solutions to the equation below?
Check all that apply.

Answer 1

Answer:

f) $x=-3+2\sqrt{5}$

b) $x=-3-2\sqrt{5}$

Step-by-step explanation:

$x^2+6x+9=20$

$x^2+6x+9-20=0$

$x^2+6x-11=0$

a = 1 (there is an invisible 1 in front of $x^2$)

b = 6

c = -11

$x=\frac{-b±\sqrt{b^2-4ac} }{2a}$

$x=\frac{-6±\sqrt{6^2-4*1*(-11)} }{2*1}$

$x=\frac{-6±\sqrt{36-4*(-11)} }{2}$

$x=\frac{-6±\sqrt{36+44} }{2}$

$x=\frac{-6±\sqrt{80} }{2}$$x=\frac{-6±4\sqrt{5}}{2}$

$x=\frac{-6+4\sqrt{5}}{2}$

$x=\frac{-6-4\sqrt{5}}{2}$

$x=-3+2\sqrt{5}$

$x=-3-2\sqrt{5}$

$x=-3+2\sqrt{5}$

$x=-3-2\sqrt{5}$

Hope this helps!