Math Help Part 1 (Please Help)

Answer:
[tex]EY=56[/tex]
[tex]DW=70[/tex]
[tex]ZE=53[/tex]
Step-by-step explanation:
[tex]YW \ \textsf{is the bisector of }EF \implies FW=EW=70\\\\EY =\sqrt{EW^2-YW^2}=\sqrt{70^2-42^2}=56[/tex]
[tex]XW \ \textsf{is the bisector of } DF \implies DW=FW=70[/tex]
[tex]ZW \ \textsf{is the bisector of }DE \implies ZE = \dfrac12DE\\\\DE=106 \implies ZE = \dfrac{106}{2}=53[/tex]