What is the value of x, rounded to the nearest tenth?

Answer:
x ≈ 31.8
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 12² = 34²
x² + 144 = 1156 ( subtract 144 from both sides )
x² = 1012 ( take square root of both sides )
x = [tex]\sqrt{1012}[/tex] ≈ 31.8 ( to the nearest tenth )
Answer:
20.8
Step-by-step explanation:
[tex]24 = \sqrt{ {12}^{2} + {x}^{2} } [/tex]
[tex] {24}^{2} = 144 + {x}^{2} [/tex]
[tex]576 - 144 = {x}^{2} [/tex]
[tex] {x}^{2} = 432[/tex]
x=20.8