Respuesta :
Answer:
the system will be worth $1892.25 after 2 years.
Explanation:
as the value decreases: [tex]\sf A = P(1 - \frac{r}{n})^{nt}[/tex] ......notice the ' - ' as its *decreases*
given:
- P = 2500
- n = 1 per year
- t = 2 years
- r = 13%
solve:
[tex]\sf A = 2500(1 - \frac{0.13}{1})^{1*2}[/tex]
[tex]\sf A = 1892.25[/tex]
another way of doing it easily is:
[ $2500 * (100- 13)% ] * (100- 13)% = $1892.25
- P=2500
- r=13
- t=2
Use compound interest formula
[tex]\\ \rm\hookrightarrow P(1-r/100)^t[/tex]
[tex]\\ \rm\hookrightarrow 2500(1+0.13)^2[/tex]
[tex]\\ \rm\hookrightarrow 2500(0.87)^2[/tex]
[tex]\\ \rm\hookrightarrow 2500(0.76)[/tex]
[tex]\\ \rm\hookrightarrow 1900[/tex]