The solutions of the equation are 20 and 160 degrees
Solution to trigonometry equation
Given the following equation expressed as:
2sin(3x) = √(3)
Divide both sides by 2 to have:
2sin(3x)/ 2= √3/2
sin3x = √3/2
Take arcsin of both sides
arcsin(sin3x) = arcsin(√3/2)
3x = 60
x = 20 degrees
Other solutions to the system of equation will be 160 degrees
Hence the solutions of the equation are 20 and 160 degrees
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