Question

Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound? A. 2. 13 × 1023 B. 4. 26 × 1023 C. 2. 57 × 1024 D. 3. 37 × 1024 E. 7. 08 × 1024.

Answer 1

The atoms of potassium (K) are in 235 grams of the compound is

2.57×$10^{24}$

Atoms are the smallest division of the element. The potassium atoms present in the 235 gm of the compound is  atoms.

What is the number of atoms?

Mass (m) of Potassium sulfide  = 235 gm

Molar mass (M) of  Potassium sulfide = 110.26 g/mol

Calculate the number of moles as:

$moles(n)=\frac{mass }{molar mass}$

$n=\frac{235}{110.26}$

=2.13 moles

In the given compound $k_2s$, there are two atoms of potassium and one atom of sulfur.

What is the value of 1 mole of potassium?

1 mole =  2×6.022 ×$10^{23}$  atoms of potassium

If 1 mole =  2×6.022 ×$10^{23}$  atoms of potassium

Then, 2.13 moles = X atoms

Solving for X

2.13× 2×6.022×$10^{23}$=2.57×$10^{24}$

Therefore, option c is correct.

The atoms of potassium (K) are in 235 grams of the compound is

2.57×$10^{24}$.

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