The probability that the employee is a male, given that the employee is less than 30 years old is given by: Option A: 0.3 (approx)
For two events A and B, by chain rule, we have:
[tex]P(A \cap B) = P(B)P(A|B) = P(A)P(B|A)[/tex]
where P(A|B) is probability of occurrence of A given that B already occurred, ( and vice versa for P(B|A) )
For the given case, naming the events as:
A = Randomly selected employee being a male
B = Randomly selected employee being less than 30 years old
Then, by the specified data, we've got:
By using the chain rule, we get:
[tex]P(B)P(A|B) = P(A)P(B|A)[/tex]
Thus, the value of P(A|B) is:
[tex]P(B)P(A|B) = P(A)P(B|A)\\\\P(A|B) = \dfrac{P(A)P(B|A)}{P(B)} = \dfrac{0.6 \times 0.4}{0.7} \approx 0.34[/tex]
Thus, the probability that the employee is a male, given that the employee is less than 30 years old is given by: Option A: 0.3 (approx)
Learn more about probability here:
brainly.com/question/1210781