Question

In a saturated solution of zn(oh)2 at 25°c, the value of [oh-] is 2. 0 x 10-6 m. What is the value of the solubility-product constant, ksp, for zn(oh)2 at 25°c ?.

Answer 1

In a saturated solution of Zn(OH)₂ at 25°c, the solubility product constant is 4.0 × 10⁻¹⁸.

What is the solubility product constant?

The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution.

• Step 1. Write the solution equation.

Zn(OH)₂(s) ⇄ Zn²⁺(aq) + 2 OH⁻(aq)

• Step 2. Make an ICE chart.

        Zn(OH)₂(s) ⇄ Zn²⁺(aq) + 2 OH⁻(aq)

I                                0                   0

C                              +S               +2S

E                                S                  2S

We can find the value of S.

[OH⁻] = 2S = 2.0 × 10⁻⁶ M

S = 1.0 × 10⁻⁶ M

We input these values in the Ksp expression.

Ksp = [Zn²⁺] [OH⁻]² = S (2S)² = 4 S³ = 4 (1.0 × 10⁻⁶)³ = 4.0 × 10⁻¹⁸

In a saturated solution of Zn(OH)₂ at 25°c, the solubility product constant is 4.0 × 10⁻¹⁸.

Learn more about Ksp here: https://brainly.com/question/25134328