The equation of the line perpendicular to x-8y = 16 and passes through the point (2,-2) is y = -8x + 14.
Linear equation
A linear equation is in the form:
y = mx + b
where m is the rate of change (slope) and b is the y intercept.
Given the line is x - 8y = 16:
8y = x - 16
y = x/8 - 2
The slope of the line is 1/8, the slope of the line perpendicular is -8. Hence, since it passes through (2 -2):
y - (-2) = -8(x - 2)
y = -8x + 14
The equation of the line perpendicular to x-8y = 16 and passes through the point (2,-2) is y = -8x + 14.
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