The angle of depression the cable forms is the arctan of the ratio of the
horizontal distance to the height of the tower which is approximately 35°.
Response:
B. 35°
Given:
Height of the tower = 500-feet
Horizontal distance from the (other) point of attachment of the cable to
the base of the tower = 350-feet.
Required:
The angle of depression formed by the cable.
Solution:
The angle of depression is the angle, θ, the cable forms with the tower
from the top of the tower.
By trigonometric ratios, therefore;
[tex]tan(\theta) = \mathbf{\dfrac{Horizontal \ distance \ of \ cable \ from \ tower}{Height\ of \ tower}}[/tex]
Which gives;
[tex]tan(\theta) = \dfrac{350}{500} = \dfrac{7}{10}[/tex]
The best correct option is; B. 35°
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