Question

Find the new concentration of a solution if 25. 0 mL of water is added to 125. 0 mL of 0. 150 M NaCl solution. What is the final volume? mL.

Answer 1

Part A: The final volume of the new solution is 150 mL.

Part B: The concentration of the new solution is 0.125 M.

What is the volume?

The volume of liquid is defined as the amount of liquid in a three-dimensional container. Volume is the quantity of three-dimensional space occupied by a liquid.

Given that the molarity of NaCl solution is 0.150 M, the volume of NaCl solution is 125 mL, the volume of water added is 25 mL.

Part A:

The final volume of the new concentrated solution is calculated as given below.

$V = 125 + 25$

$V = 150 \;\rm mL$

The final volume of the new solution is 150 mL.

Part B:

The mole of the NaCl solution is calculated using the molarity formula.

Molarity of NaCl solution = 0.150 M

Volume of NaCl solution = 125mL or 0.125 L

Molarity = Mole of NaCl solution / Volume of the NaCl solution

$0.150 = \dfrac {Moles}{Volume}$

$0,150 = \dfrac {Moles}{0.125}$

$Moles \;= 0.01875$

The moles of NaCl solution is 0.01875 mole which remains same when water is added. Thus, the molarity of the new concentration can be calculated as given below.

Molarity = Moles of NaCl / Volume of new solution

Molarity = $\dfrac {0.01875}{0.150}$

Molarity = 0.125 M

Hence we can conclude that the concentration of the new solution is 0.125 M.

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