Question

$\frac{5(1-2x)}{3} +\frac{x}{2} =\frac{3(x-5)}{4}-2$

Answer 1

Answer:

x=89/43

Step-by-step explanation:

$\dfrac{5(1-2x)}{3} +\dfrac{x}{2} =\dfrac{3(x-5)}{4}-2\\\\\\\implies \dfrac{10(1-2x)}{6} +\dfrac{3x}{6} =\dfrac{3(x-5)}{4}-\dfrac84\\\\\\\implies \dfrac{10(1-2x)+3x}{6} =\dfrac{3(x-5)-8}{4}\\\\\\\implies \dfrac{10-17x}{6} =\dfrac{3x-23}{4}\\\\\\\implies 4(10-17x) =6(3x-23)\\\\\implies 40-68x=18x-138\\\\\implies 86x=178\\\\\implies x=\dfrac{89}{43}$

Answer 2

Answer/Step-by-step explanation:

We are trying to isolate the variable.

Multiply both sides by 6 (to get rid of fraction on left side)

10(1-2x)+3x=[9(x-5)]/2 -12

Multiply both sides by 2 (to get rid of fraction on right side)

20(1-2x)+6x=9(x-5)-24

expand

20-40x+6x=9x-45-24

simplify

20-34x=9x-69

move x to one side

20=43x-69

move numbers to one side

89=43x

x=2.0697