Question

water flows through a horizontal pipe with a cross-sectional area of 4m^2 at a speed of 5m/s with a pressure of 300,000pa at point a at point b the cross sectional area is 2m^2. what is the speed of water at point B? calculate the pressure at point B​

Answer 1

The velocity at point B is 10 m/s with a pressure of 262500 Pa

Bernoulli equation

According to the continuity equation:

A₁V₁ = A₂V₂

Where A is the area and V is velocity, ρ = density of water = 1000 kg/m³

Hence:

4(5) = 2(V₂)

V₂ = 10 m/s

Using Bernoulli equation:

$P_1+\rho gh_1+\frac{1}{2}\rho V_1^2= P_2+\rho gh_2+\frac{1}{2}\rho V_2^2\\\\Hence:\\\\300000+\rho gh+(0.5)*1000*5^2=P_2+\rho gh+(0.5)*1000*10^2\\\\P_2=262500\ Pa$

The velocity at point B is 10 m/s with a pressure of 262500 Pa

Find out more on Bernoulli equation at: https://brainly.com/question/14082066