Question

14. There are 11 boys and 10 girls in a classroom. A teacher chooses a student at random and puts that student
at the head of a line, chooses a second student at random and makes that student second in the line, and
so on, until all 21 students are in the line. What is the probability that the teacher puts them in a line
alternating boys and girls? where no two of the same gender stand together?

Answer 1

Yes because if she's going one in one out it is a chance thats what shes doing

Answer 2

The probability that the teacher puts them in a line alternating boys and girls is 1/352714

What is probability?

Probability is the likelihood that an event will occur and is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

Given: There are 11 boys and 10 girls in a classroom.

A teacher chooses a student at random and puts at the head of a line.

Number of students=  $^{21}P_{21}$/ 11 ! * 10!

                         = 21 !/11!*10!

                         = 21*20*19*18*17*16*15*14*13*12*11!/11!* 10*9*8*7*6*5*4*3*2*1

                         = 352714

P(alternate boys and girls)= n(A)/n(S)

                                           = 1/ 352714

Learn more about probability here:

brainly.com/question/11234923

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