Question

How large is the acceleration of a 35-kg mass that has a net force of 270 N applied to it horizontally? Write units as well.

Answer 1

• Mass=35kg=m
• Force=F=270N
• Acceleration be a

Using Newton's second law

$\\ \rm\hookrightarrow F=ma$

$\\ \rm\hookrightarrow a=F/m$

$\\ \rm\hookrightarrow a=270/35$

$\\ \rm\hookrightarrow a=7.7m/s^2$

Answer 2

We will find the acceleration using the formula of force. The formula states that the net force applied on an object is directly proportional to the product of mass of the body and the acceleration of the body...

$\mathcal{F = MA}$

Where,

• F is force
• M is mass
• A is acceleration

In our case,

• F = 270 N
• M = 35 kg
• A = Unknown

$\large\underline{\underline{\maltese{\orange{\pmb{\sf{\: Solution :-}}}}}}$

• $\green \leadsto \purple{ \tt 270 = 35 \times a}$
• $\green \leadsto \purple{ \tt 270 = 35 a}$
• $\green \leadsto \purple{ \tt 35a = 270}$
• $\green \leadsto \purple{ \tt 35a \div 35 = 270 \div 35}$
• $\green \leadsto \purple{ \tt a = 7.7 \: {m/s}^{2} }$

➪ Therefore, The acceleration of the body is 7.7 m/s²...~