»f(x) = (x + 2)²
»f(5) = (5 + 2)²
»f(5) = 7²
»f(5) = 49✅
~Hello! I will try to help you!
•Given : -
•To Find : -
•Step-by-step explanation : -
[tex] \Rightarrow \sf f(x) = {x}^{2} + 4x + 4[/tex]
»Just substitute the value 5 into the function f(x) above, then:-
[tex] \Rightarrow \sf f(5) = {5}^{2} + 4(5) + 4 \\ \Rightarrow \sf f(5) = 25 + 20 + 4 \\ \Rightarrow \sf f(5) = \bf49[/tex]
With this it's done!